Answer:
No
Step-by-step explanation:
An extraneous solution is a root of a transformed equation which is not a root of the original equation because it was not included in the domain of the original equation.
Ahmed is solving ![2\sqrt[3]{x-7}+11=3](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7Bx-7%7D%2B11%3D3)
for x.
His steps were:
![\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D2%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-8%5C%5C%20%20%5Csqrt%5B3%5D%7Bx-7%7D%26%3D-4%5C%5C%20%20%5Cleft%28%5Csqrt%5B3%5D%7Bx-7%7D%5Cright%29%5E3%26%3D%28-4%29%5E3%5C%5C%20%20x-7%26%3D-64%20%5Cend%7Baligned%7D)
Since cube roots <u>do not give two solutions when solved</u>, it is <u>not necessary </u>to check his answers for extraneous solutions.
Answer:
third one down
Step-by-step explanation:
H< 30
That is your inequality.
Answer:
3. d= 20mm
4. r= 8 in
5. d= 14 mi
6. r= 11 yd
Step-by-step explanation:
Radius is half of diameter.
Example:
What is the diameter of a circle with a radius of 4?
If r = 4, d = 8
Do radius times 2.
Example 2:
What is the radius of a circle with a diameter of 10?
D = 10, so r = 5
Do diameter divided by 2.
Answer:
yep this kinda hard!!!!!!!!!!!!?!??!
