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1 year ago

Plz answer quick I need to get it bc it’s a quiz

Mathematics

2 answers:

ZanzabumX [31]1 year ago

8 0

Answer:

slope equals 2

Step-by-step explanation:

graph points and calculate rise over run

WARRIOR [948]1 year ago

3 0

The answer is 2 the slope is 2.

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Josephine is taking a college course, and her professor bases the course grade on the average of 2 tests taken in the semester.

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b = 2A - a

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(a + b)/2 = A

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2 years ago

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Han buys an item with a normal price of $15.

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$1.50

Step-by-step explanation:

15*.10=1.50

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2 years ago

A plant grows the same amount every week. Which graph matches the situation described? b e .

dem82 [27]

Answer:

Option A

Step-by-step explanation:

Let the height of plant is 'b' units.

Graph representing the height of the plant will have y-intercept = b units

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2 years ago

The perimeter of a rectangular field is 364 yards. If the width of the field is 84 yards, what is its length?

elena55 [62]

The perimeter of a rectangular field is 364 yards. If the width of the field is 84 yards, what is its length?

(364 : 2) - 84 =

182 - 84 =

3 0

2 years ago

A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$

To maximize the area, we derive and equal to zero:

$\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36$

Then, b is:

$b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68$

3 0

2 years ago