Factorize x²+7x+12 ===> (x+3)(x+4)
Factorize x²-3x-28 ===> (x-7)(x+4)
4x + 12 can be written====> 4(x+3)
Then the question could be written as follows:
[(x+3)(x+4) / (x-7)(x+4) ] / 4(x+3) = [(x+3)(x+4) / (x-7)(x+4) ].[4(x+30]
After simplification you get 1 / 4(x-7)
Answer: x-3, 3, is not equal to
Step-by-step explanation:
The answer to your problem is 1300.
Answer:
The two angles ADB and BDC are congruent since they are both right angles.
The segment AD and CD are congruent since D is the midpoint of AC.
Segment BD is in common for the two triangles.
The triangles ABD and BCD are congruent by SAS. In particular, Angle A is congruent to angle C (they are opposite to congruent sides), QED