Answer:
82.97 K
Explanation:
Applying,
PV/T = P'V'/T'................ Equation 1
Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
Make T' the subject of formula in equation 1
T' = P'V'T/PV................ Equation 2
From the question,
Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L
Substitute these values into equation 2
T' = (0.327×10.41×222.2)/(1.154×7.9)
T' = 82.97 K
Hence the new temperature is 82.97 K
P = 1.5atm ≈ 1519.88hPa
V = 8.56L
R = 83.1 [hPa*L] / [mol*K]
T = 0°C =273K
pV = nRT |:RT
n = pV / RT
n = [1519.88hPa*8.56L] / [83.1 [hPa*L] / <span>[mol*K] * 273K]
n </span>≈ <u>0.57mol</u><span><u> </u></span>
Answer:
I will give up the electrons
Explanation:
Consider the following rules:
1. An atom loses electrons if its oxidation number is positive.
2. An atom gains electrons if its oxidation number is negative.
3. An atom neither gains nor loses electrons if its atomic number is zero.
As I have an oxidation number that is oxidation number is positive, so, I will give up electrons.
Answer: The volume of boron trifluoride gas that is collected is 18.6 L
Explanation:
According to the ideal gas equation:
PV=nRT
P = Pressure of the gas = 1 atm
V= Volume of the gas= ?
T= Temperature of the gas in kelvin =
R= Gas constant =
n= moles of gas= 854 mmol = 0.854 mol (1mmol=0.001mol)
Thus volume of boron trifluoride gas that is collected is 18.6 L