<span>a. Use PV = nRT and solve for n = number of mols O2.
mols NO = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols O2 to mols NO2. Do the same for mols NO to mols NO2. It is likely that the two values will not be the same which means one is wrong; the correct value in LR (limiting reagent) problems is ALWAYS the smaller value and the reagent producing that value is the LR.
b.
Using the smaller value for mols NO2 from part a, substitute for n in PV = nRT, use the conditions listed in part b, and solve for V in liters. This will give you the theoretical yield (YY)in liters. The actual yield at these same conditions (AY) is 84.8 L.
</span>and % will be 60%.
Answer:
See explanation
Explanation:
Matter may exist in three phases; solid, liquid and gas. The state in which matter exists depends on the extent of intermolecular forces operating in the substance.
In solid particles, the molecules that compose the solid are close together because the molecules of a solid do not move from place to place but they continue to vibrate about their fixed position.
For liquids, the molecules that compose a liquid are in random motion but are less energetic than molecules of a gas.
In gases, the molecules are not held together at all. The molecules of a gas have the highest degree of freedom. They move from one point another at a high velocity.
Hence, the order of increasing degree of movement of the particles in different states of matter = solids<liquids< gases.
Solids have well arranged particles, the molecules of a liquid are a little more disorderly than liquid particles while gas particles are the most disorderly of all the states of matter.
the answer is 133
because thats how the water is
Hi
I think it’s B
Hopefully this helps!!
If the forward reaction goes close to completion and has a high yield, that means the concentration of products will be higher than the concentration of reactants.
<span>So if the concentration of products is higher, Kc (equilibrium constant) will be greater than 1.
</span><span>
Recall the calculation for the equilibrium constant for reaction. Picture below might help you.</span>
