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2 years ago

8

7th Grade Math Please help I will give brainliest!! 19 = 5/3 r Find the value of r

1 answer:

Scilla [17]2 years ago

8 0

Answer:

$\huge\boxed{r=\dfrac{57}{5}\to r=11\dfrac{2}{5}\to r=11.4}$

Step-by-step explanation:

$19=\dfrac{5}{3}r\to\dfrac{5}{3}r=19\qquad|\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup\cdot\dfrac{5}{3\!\!\!\!\diagup}r=19\cdot3\\\\5r=57\qquad|\text{divide both sides by 5}\\\\\dfrac{5r}{5}=\dfrac{57}{5}\\\\r=\dfrac{57}{5}\to r=11\dfrac{2}{5}\to r=11.4$

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2 years ago

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1 year ago

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

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Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

2 years ago