You can Draw a segment WY connecting the centers<span> of the </span>two circles<span>, and then draw a segment, WS, so that YS + SZ = YZ and WS ⊥ YZ).</span>
Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8
1 persona pagaba 341 por ida y 298 por venido lo que significa que 1 persona paga en total= 639
si son 16 seria= 639*16=10224 en total
Answer:
The answer is just re look at the question A
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
