<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
Russia shut off the Nord Stream pipeline that supplies natural gas to Germany.
What is the Nord Stream pipeline?
A pair of offshore natural gas pipeline systems in Europe called Nord Stream cross the Baltic Sea from Russia to Germany. It consists of the Nord Stream 1 and Nord Stream 2 pipelines, both of which originate in northwest Russia, near Finland, in Vyborg and Ust-Luga, respectively. Both pipelines travel to Lubmin in the Mecklenburg-Vorpommern state of northeastern Germany.
Due to Russia's invasion of Ukraine, certification for Nord Stream 2 has been rejected. When referring to a larger network of pipelines, such as the feeding onshore pipeline in Russia and additional connections in Western Europe, the term "Nord Stream" is sometimes used.
Nord Stream joins the NEL pipeline to Rehden near Bremen in northwestern Germany and the OPAL pipeline to Olbernhau in eastern Germany at the Czech border in Lubmin.
Thus, the Nord Stream pipeline supplies natural gas to Germany.
Learn more about the natural gas pipeline here,
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Answer: 2940 J
Explanation: solution attached:
PE= mgh
Substitute the values:
PE= 10kg x 9.8 m/s² x 30 m
= 2940 J
Answer:
ΔV=0.484mV
Explanation:
The potential difference across the end of conductor that obeys Ohms law:
ΔV=IR
Where I is current
R is resistance
The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A
R=(pL)/A
Given data
Length L=3.87 cm =0.0387m
Diameter d=2.11 cm =0.0211 m
Current I=165 A
Resistivity of aluminum p=2.65×10⁻⁸ ohms
So
ΔV=IR
ΔV=0.484mV
