To solve using completing square method we proceed as follows:
x^2-10x+8=0
x^2-10x=-8
but
c=(b/2)^2
c=(10/2)^2=25
thus we can add this in our expression to get
x^2-10x+25=8+25
factorizing the LHS we get:
(x-5)(x-5)=33
(x-5)^2=33
getting the square roots of both sides we have:
x-5=+/-√33
x=5+/-√33
The answer to the question
Answer and explanation:
They are not equivalent because if we simplify the second expression, the result isn't the same:
7(y×b)+3b
= 7(yb)+3b
=7yb + 3b
Therefore 7yb+3b≠7y+7b+3y
And even though you meant
7(y+b)+3b
=7y+7b+3b
=7y+10b
7y+10b≠10y+7b
Answer:
3.1 3.25 3.33 3.4
Step-by-step explanation: