Please help with this math problem

Mathematics

1 answer:

zimovet [89]2 years ago

3 0

$x=2+½*\sqrt{10}$

$x=2-½*\sqrt{10}$

Answer:

Solution given:

y=2x²-5x+6.....[1]

y=3x+3.........….[2]

solving equation 1&2

2x²-5x+6=3x+3

2x²-5x-3x+6-3=0

2x²-8x+3=0

comparing above equation with ax²+bx+c=0 we get

a=2

b=-8

c=3

by using quadratic equation

$x=\frac{+8±\sqrt{(-8)²-4*2*3}}{2*2}$

$x=\frac{+8±2\sqrt{10}}{4}$

taking positive

$x=\frac{+8+2\sqrt{10}}{4}$

$x=2+½*\sqrt{10}$

taking negative

$x=2-½*\sqrt{10}$

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A bowling leagues mean score is 197 with a standard deviation of 12. The scores are normally distributed. What is the probabilit

Bond [772]

Answer:

0.281 = 28.1% probability a given player averaged less than 190.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A bowling leagues mean score is 197 with a standard deviation of 12.

This means that $\mu = 197, \sigma = 12$