Find the are of the pool by dividing the volume by the depth:
1960 / 4 = 490
The pool is 490 square feet.
Area is found by multiplying the length by the width.
Let the width = X
We are told the length is 2.5X ( 2.5 times longer)
So we now have 2.5x * x = 490
2.5x * x = 2.5x^2
Now we have 2.5x^2 = 490
Divide both sides by 2.5:
x^2 = 490/2.5
x^2 = 196
find X by taking the square root of 196:
x = √196
x = 14
The width is 14 feet
The length is 2.5 * 14 = 35 feet
Answer: (B) 30 gallons.
Step-by-step explanation: Lets subtract 110 - 78 to find the maximum amount of additional water, w that can be added to the tub.
110 - 78 = 32.
round 32 to 30.
So, a reasonable value would be 30 gallons.
Answer:
32%
Step-by-step explanation:
Area of rectangle ABCD = 20 * 30 = 600 Sq cm
After increasing the length and width of the rectangle by 20% and 10% respectively.
New length = 30 + 20% of 30 = 30 + 6 = 36 cm
New width = 20 + 10% of 20 = 20 + 2 = 22 cm
Area of new rectangle = 36*22 = 792 Sq cm
Increase in area = 792 - 600 = 192 Sq cm
Percentage increase in area
= (192/600) *100
= 32%
Take any 2 points the answer will be the same.
For point 2 and 3 : (-4)-(2)/(0)-(-1) = -6
the answer is -6
I can help with the formula just do the math on a calculator you multiply length x width x height