Answer:
x^2-12x+36
Step-by-step explanation:
The first step in solving this equation is to expand the square which makes the equation (x-6)(x-6). Then you distribute the x to both parentheses which leaves you with x^2-6x, and then you distribute the 6 to both parentheses which gives you 6x+36. Then add both binomials which leaves you with x^2-12x+36. The reason it is +36 and not -36 is because you are multiplying a negative 6 by another negative 6.
Answer:
the first on is 144 the secnd one is 1
Step-by-step explanation:
i think that's write.
The area of the trapezoid is x+11 cm.
Given a trapezoid has one side of (x+6) cm, the other side is 5 cm, and the height is 2 cm.
A two-dimensional quadrilateral consisting of the sum of non-adjacent parallel sides and a suitable non-parallel side is denoted as a trapezoid.
Now we will use the formula to find the area of a trapezoid
Area = 1/2 × (base 1 + base 2) × height
Here base 1 = (x+6) cm, base 2 = 5cm and height = 2cm
Substituting the values into the formula, we get
Area = 1/2 × (x+6+5) × 2
Area = 1/2 × (x+11) × 2
Area = x+11
Thus, the area of the given figure when one side is x+6, the other side is 5 cm and the height is 2 cm is x+11 cm.
Learn more about the area of trapezium from here brainly.com/question/15815316
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Hello from MrBillDoesMath!
Answer:
72
Discussion:
Total Surface area = area of pyramid base + 4 ( area of triangular face)
In our case this becomes
4*4 + 4( (1/2) (4)(7) ) =
= 16 + (2)(4)(7)
= 16 + 56
= 72
which is the first choice.
Note: the area of a triangular face was computed using (1/2) b h, which in our case is
(1/2) (4) (7)
Thank you,
MrB
Answer:
Minimum total cost = $20550
maximum revenue $44,100
Step-by-step explanation:
Given data:
Production cost $5.55 per unit
Fixed cost = $15000 per month
Price, p = 42-0.01 q
where. q represent number of unit produced
revenue can be wriiten as
p.q = 42q - 0.01q^2
1) from information 1000 unit has to produced therefore
total cost = 15000 + 5.55×1000 = $20550
Minimum total cost = $20550
2) Revenue = 42q - 0.01q^2
therefore for maximum revenue q is = 2100
so, maximum revenue
= $44,100