All categories

2 years ago

Which first step for solving the given system using substitution results in an equation wit

Mathematics

1 answer:

Paraphin [41]2 years ago

8 0

I don’t know if I’m right but I got 2/3 but you should use desmos

You might be interested in

Three girls cut out decimal models of hundredths. Amber doesn't shade any of her models. Grace qualifies three fifths of a model

Varvara68 [4.7K]

Answer:

$Amber = 0$

$Grace = 0.60$

$Marsha =1.70$

Step-by-step explanation:

Given

<em>Decimal Grid = Hundredths</em>

$Amber = None$

$Grace = \frac{3}{5}th$

$Marsha = 1 + \frac{7}{10}th$

To solve for each:

We have:

For Amber:

$Amber = 0 * 100$

$Amber = 0$

For Grace:

$Grace = \frac{3}{5}th$

$Grace = \frac{3}{5} * 100$

$Grace = \frac{300}{5}$

$Grace = 60$

This means that Grace shaded 60 of the hundredth models.

Decimal shaded is:

$Grace = 60 * \frac{1}{100}$

$Grace =\frac{60}{100}$

$Grace = 0.60$

For Marsha:

$Marsha = 1 + \frac{7}{10}th$

$Marsha = \frac{10 + 7}{10}th$

$Marsha = \frac{17}{10}th$

$Marsha = 1.7th$

Multiply this by 100, to get the number of shaded

$Marsha = 1.7 * 100$

$Marsha = 170$

This means that Marsha shaded 170 of the hundredth models.

Decimal shaded is:

$Marsha = \frac{170}{100}$

$Marsha =1.70$

5 0

2 years ago

Evaluate C = 2 r, for r = 8.

Jet001 [13]

Answer:

C = 16

Step-by-step explanation:

Substitute r = 8 into the equation for C, hence

C = 2r = 2 × 8 = 16

4 0

2 years ago

Read 2 more answers

The value of a car declined 20% per year. what percent of the original value remains after 2 years

GalinKa [24]

60% is answer...20% is taken each year so After 2 yrs it's 40% less 100-40 is 60

5 0

3 years ago

A and B working together can do a work in 6 days. If A takes 5 days less than B to finish the work, in how many days B alone can

svetlana [45]

Answer:

15 days

Step-by-step explanation:

Let x be the number of days needed for B to complete the job. Then x-5 is the number of days needed for A to complete the job.

In 1 day,

A completes $\dfrac{1}{x-5}$ of all work;
B completes $\dfrac{1}{x}$ of all work.

Hence, in 1 day both A and B complete $\dfrac{1}{x-5}+\dfrac{1}{x}$ of all work. A and B working together can do a work in 6 days. Then

$6\cdot \left(\dfrac{1}{x-5}+\dfrac{1}{x}\right)=1.$

Solve this equation:

$\dfrac{6x+6x-30}{x(x-5)}=1,\\ \\12x-30=x^2-5x,\\ \\x^2-17x+30=0,\\ \\D=(-17)^2-4\cdot 30=289-120=169=13^2,\\ \\x_{1,2}=\dfrac{17\pm 13}{2}=2,\ 15.$

If $x=2,$ then $x-5=-3$ that is impossible. So, B needs 15 days to complete the work alone.

6 0

2 years ago

A rectangle has a perimeter of 16p centimeters. It has a width of 2p centimeters. Find the length of the rectangle in terms of p

DIA [1.3K]

If the width is 2p then the width of both sides is 4p. Subtract that from the total perimeter and you get 16p-4p= 12p. Divide that by two because there are 2 side lengths. So, one side length is 6p.

6 0

2 years ago

Read 2 more answers