10 Inches
A = p q / 2
p = diagonal 1
q = diagonal 2
2A / q = p
Solve for p
180/18 = 10
If it decreases by 80٪, then only 20٪ remains.
15×20٪=15×20/100=15×0.2=3
Answer: 3
Answer:
The width of member is as follows:
b = 3 ft
b = 3 × 12 in.
b= 36 in.
The depth of member is as follows:
d = 8 ft
d = 8 × 12 in.
d=96 in.
Since the structure used is Douglas fir-Larch lumber of size 3 × 8 size. Hence, tensile strength, f =1000 psi
Calculate the net area of the member as follows:
A = (b - ∅) × d
A= (36 - 7/8) × 96
Calculate the maximum axial tensile load by ASD method as follows:
P = f × A
P = 1000 x 3372
P = 3372000 lbs
P = 3372 kips
the answer of this question is 38 and i hope it s correct
The markup is $46.25 and the final price is $231.25