Ask question

Ask question

All categories

Karo-lina-s [1.5K]

2 years ago

5

A flagpole is 10m high. It is held in position by four ropes that are each fixed to the ground, 4m away from the foot of the fla

gpole, to make a square. The diagram shows the flagpole and two ropes that are opposite each other. Calculate the length of each rope

1 answer:

drek231 [11]2 years ago

8 0

Answer:

10.77m

Step-by-step explanation:

You might be interested in

How many trees is 10000=35=3=5=43===56=46=4=5=7=457=457457

Anton [14]

Answer:

PUPPY DOGGIE

Step-by-step explanation:

REEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

6 0

2 years ago

5x 20 and the. multiplicative inverse of 5

ehidna [41]

That is 5*20 is 100 and the inverse of 5 is 25

8 0

2 years ago

ΔABC has vertices A(2,4), B(6,0), AND C(-4,0).

arlik [135]

<span>ΔABC is not a right triangle.</span>

3 0

2 years ago

Read 2 more answers

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago

Function P is represented as y = 1 2 x + 4 . Function Q is graphed. Which statement is correct? The slope of function Q is 1 2 t

vivado [14]

Answer:

jjj

Step-by-step explanation:

uidjfhthbtjdihiff

4 0

2 years ago