How can i put the number 103,727,495 in expanded form
You can put the number 103, 727,495 in expanded form by:
<span><span>1.
</span>100, 000, 000 + 3,000, 000 + 700,000 + 20, 000 +
7, 000 + 400 + 90 + 5</span>
Which in words is.
<span><span>1.
</span>One hundred three million seven hundred twenty
seven thousand four hundred ninety-five </span>
Answer:
Hundredths place
Step-by-step explanation:
6 in 6.54 is ones place
5 in 6.54 is tenths place
4 in 6.54 is hundredths
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Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)
The 68-95-99.7 rule tells us 68% of the probability is between -1 standard deviation and +1 standard deviation from the mean. So we expect 75% corresponds to slightly more than 1 standard deviation.
Usually the unit normal tables don't report the area between -σ and σ but instead a cumulative probability, the area between -∞ and σ. 75% corresponds to 37.5% in each half so a cumulative probability of 50%+37.5%=87.5%. We look that up in the normal table and get σ=1.15.
So we expect 75% of normally distributed data to fall within μ-1.15σ and μ+1.15σ
That's 288.6 - 1.15(21.2) to 288.6 + 1.15(21.2)
Answer: 264.22 to 312.98
I think you meant 5,244 ÷ 6 = 874.
Answer/Step-by-step explanation:
We can check if this 5,244 ÷ 6 = 874 is correct by doing it opposite.
Since it 5,244 divide 6 we can do 874 x 6.
![\left[8 7 4] \\](https://tex.z-dn.net/?f=%5Cleft%5B8%20%20%207%20%20%204%5D%20%5C%5C)
× ![[6]](https://tex.z-dn.net/?f=%5B6%5D)
======
+ 5244
=======
5244
Hence, this answer is correct.
[RevyBreeze]
