All categories

2 years ago

Brainlyst for the best answer thank you!

Mathematics

1 answer:

densk [106]2 years ago

6 0

Answer: B

We all know that area= LxW
The width that is being shown is 8ft. The length is 20ft. Therefore, you multiply 8 x 20 which gives you 160ft squared. Hope this this helps :)

You might be interested in

What is the value of n 9 times 27+2 times31-28

Kay [80]

9•27+2•31-28= ? Is that what you are asking?

8 0

2 years ago

What is the volume of the rectangular prism in the figure shown?

ra1l [238]

We know that, Volume of a Rectangular Prism is given by :

✿ {Length × Width × Height}

Given : The Length of Rectangular Prism = 5.5

Given : The Width of Rectangular Prism = 6

Given : The Height of Rectangular Prism = 3

⇒ The Volume of given Rectangular Prism = {5.5 × 6 × 3}

⇒ The Volume of given Rectangular Prism = 99

3 0

2 years ago

Read 2 more answers

Simplify 3 - b (7b + 2) + 3b - (11 - b)

nirvana33 [79]

Answer: -7b² + 2b - 8

Step-by-step explanation:

Given expression

3 - b (7b + 2) + 3b - (11 - b)

Expand parentheses and apply the distributive property if necessary

=3 - b · 7b - b · 2 + 3b - 11 + b

=3 - 7b² - 2b + 3b - 11 + b

Combine like terms

=-7b² + (3b - 2b + b) + (3 - 11)

= $\boxed{-7b^2+2b-8}$

Hope this helps!! :)

Please let me know if you have any questions

8 0

2 years ago

HELP!!! Choose the best answer.

Romashka-Z-Leto [24]

Answer:

the third one

Step-by-step explanation:

5 0

2 years ago

Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.

Flauer [41]

Answer:

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}$

Step-by-step explanation:

Given

$\sqrt{128a^{6}b^{13}}$

Required

Solve

$\sqrt{128a^{6}b^{13}}$

The expression can be split to:

$\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}$

$\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}$

So, we have:

$\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}$

$\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}$

Rewrite as:

$\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2} * \sqrt{b}$

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}$

$\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}$

5 0

2 years ago