Answer:
.
(Expand to obtain an equivalent expression for the sphere: )
Step-by-step explanation:
Apply the Pythagorean Theorem to find the distance between these two endpoints:
.
Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:
.
In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between and would be:
.
In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:
.
The equation for a sphere of radius and center would be:
.
In this case, the equation would be:
.
Simplify to obtain:
.
Expand the squares and simplify to obtain:
.
Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
✌ ✌ ✌ ✌
Think of PEMDAS, or Please Excuse My Dear Aunt Sally. Which is Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction in that order.
Answer:
19
Step-by-step explanation:
Given 2 sides of a triangle then the third side x is
difference of 2 sides < x < sum of 2 sides , that is
18 - 2 < x < 18 + 2
16 < x < 20
Then the largest possible length of the third side is 19