Answer: all I know it’s not -31.5 for ppl taking the k12 test
Explanation: I took the test
Answer:
D
Explanation:
gas are well separated with no regular arrangement and spreaded all over. liquid are close together with no regular arrangement and slightly spreaded. solid are tightly packed, usually in a regular pattern and not spreaded at all.
Ignoring the n's, there would only be one unpaired electron.
Answer:
Metal (appropriate charge on metal) nonmetal-ide
Explanation:
1) Write the name of transition metal as shown on the Periodic Table.
2) Write the name and charge for the non-metal.
Use the total charge on the non-metal (or polyatomic ion) find the charge on the transition metal.
3) After the name for the metal, write its charge as a Roman Numeral in parentheses. Example: Iron (II) chloride.
The idea behind balancing chemical equations is that the number of atoms an element has on the reactants' side must be equal to the number of atoms it has on the products' side.
These atoms will become a part of different compounds once the reaction is completed, but they must always be in equal numbers on both sides.
So, look at iron first. One atom reacts, but two are produced - notice the 2 subscript iron has in Fe2O3. This means you must double the number of atoms on the reactants' side to reach an equality.
2Fe(s)+O2(g)→Fe2O3(s)
Now look at oxygen. Two atoms react, but three are produced. The trick here is to find a common multiple that will make the number of atoms equal on both sides.
The easiest way to do this is to multiply the atoms that react by 3, which will give you 6 oxygen atoms that react, and the atoms that are produced by 2 - this will get you 6 oxygen atoms produced.
2Fe(s)+3O2(g)→2Fe2O3(s)
However, notice that the iron atoms are unbalanced again. You have 2 that react, but 4 that are produced → multiply the atoms that react by 2 again, which will give you
4Fe(s)+3O2(g)→2Fe2O3(s)
