The answer is 3:1.
If we imagine that plant has two alleles for the
trait, we can dominant allele represent with P represents and recessive allele with p. To get purebred monohybrid in the first generation, parents must be a dominant homozygote (PP) and a recessive hetero<span>zygote (pp):
Parental generation: PP x pp
The first generation: Pp Pp Pp Pp
Pp represents a heterozygote.
If we cross these heterozygotes:
The first generation: Pp x Pp
The second generation: PP Pp Pp pp
If dominant allele determines the phenotype, there will be 3 plants (one PP and two Pp) with one phenotype and only 1 plant </span><span>(pp)</span> with another phenotype and vice versa.
We can't read your minds we need to see the options
If the student has mass 75 kg, and if the stairs are 3 m high, then
<span>work = mgh = 75kg * 9.8m/s² * 3m = 2200 J </span>
<span>so I'd say "one one-hundredth." </span>
<span>Except that I think 5000 cal ≈ 20.95 kJ (not J), and that would change my answer to </span>
<span>"ten times or so".
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