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What volume would be needed to prepare 375 mL of a .45 M CaCl2 using only a solution of 1.0 M CaCl2 and water?
1 answer:
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Answer:
<h3>The answer is 11 g/mL</h3>Explanation:
The density of a substance can be found by using the formula
From the question
mass = 3025 g
volume = 275 mL
We have
We have the final answer as
<h3>11 g/mL</h3>Hope this helps you