Where, P is the pressure of the gas (Pa), V is the volume of
the gas (m³), n is the number of moles of gas (mol), R is the
universal gas constant ( 8.314 J mol</span>⁻¹ K⁻<span>¹)
and T is temperature in Kelvin.
</span>n = m/M
(2)
Where, n is number of moles, m is mass and M is
molar mass.
From (1)
and (2),
PV = (m/M) RT
By
rearranging, M =
(mRT)/PV (3)
P = standard pressure = 1 atm = 101325
pa V = 0.896 L = 0.896 x 10⁻³ m³ R = 8.314 J mol⁻¹ K⁻¹<span>
T = Standard temperature = 273 K m = </span>3.87 g = 3.87 x 10⁻³ kg<span> M = ? </span><span> By appying the formula, M =(</span>3.87 x 10⁻³ kg x 8.314 J mol⁻¹ K⁻¹ x 273 K) /101325 pa x 0.896 x 10⁻³m³ <span>M = 0.0967 kg M = 96.7 g.