Answer:
A. ⇒ The expression is b + 3
B. ⇒ The expression is 2b - 4
C. ⇒ The Dr's office is closer by 4 miles
Step-by-step explanation:
A.
∵ The distance between Daniel's house and his school is b miles
∵ The swimming pool is 3 miles farther from his school
∴ The distance between Daniel's house and the swimming pool is b + 3
B.
∵ The distance from Daniel's house to his Dr's office is 4 less than twice the distance from home to Daniel's school
∵ The distance between Daniel's house and his school is b
∴ The expression of distance from Daniel's house to his Dr's office is
2b - 4
C.
∵ b = 3
∴ The distance between his house and swimming pool is:
3 + 3 = 6 miles
∴ The distance between his house and Dr's office is:
2(3) - 4 = 2 miles
∴ The Dr's office is closer to Daniel's house than the swimming pool by:
6 - 2 = 4 miles
Answer:
Average speed is 37.35 mi/h
Step-by-step explanation:
given data
leave = 34 minutes before
church distance = 12.0 miles
average speed first 17 minutes = 5.0 mi/h
solution
so we find Total distance travel in first 17 minutes = speed × time
Total distance travel in first 17 minutes = 5 × 
Total distance travel in first 17 minutes = 1.416 mi
and
Distance Remaining = 12 - 1.416 = 10.584 mi
Time Remaining = 34 - 17 min = 17 min
so
remaining distance Average speed = 
Average speed = 
Average speed is 37.35 mi/h
25x/45=-65
25x=2925
x=117
I wasn't sure if you wanted a solution
