Answer: I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }
Step-by-step explanation:
Given the data in the question;
A vector is in the span of V1 and V2 only if it is a linear combination.
of V1 and V2.
so 'V' is in the span if;
V = SV1 + tV2 [ S and t are real numbers ]
V = [ 6si + 5sj ] + [ 6tj + 5tz]
V = 6s, 5s+6t, 5t
so
I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }