(1)
10(1+3x)=-20
Cross multiply.
10+30x=-20
Isolate x on one side. So you would subtract 10 on each side. and one side will cross each other out. leaving you with,
30x=-20-10
Subtract 10 from -20.
30x=-30
Divide each side by 30 to get x.
30x÷30=-30÷30
Therefore,
x=-1
(2)
-5x-8(1+7x)=-8
Cross multiply -8(1+7x)
-5x-8-56x=-8
Isolate all x's on one side. So you would add 8 on each side. and one side will cross each other out. leaving you with,
-5x-56x=-8+8
Add 8 to -8.
-5x-56x=0
Subtract -56x from -5x
-61x=0
Divide each side by -61
-61x÷-61=0÷-61
Therefore,
x=0
Answer:
Al igual que los cuadrados y los triángulos equiláteros, los hexágonos regulares encajan sin ningún espacio para enlosar el plano (tres hexágonos se encuentran en cada vértice), por lo que son útiles para construir mosaicos.
Answer:
Step-by-step explanation:
using your f(x) I want to show you how to plug in different things itnot he function.
f(x) = -x + 4
f(1) = -1 + 4 = 3
f(2) = -2 + 4 = 2
f(m) = -m + 4
f(abc) = -(abc) + 4
f(h(x)) = -h(x) + 4
Does that help? what if you replaced h(x) with g(x)? Of course you already have that x so you could make it a little simpler as well. Let me know if you don't quite get it.
