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2 years ago

6

Help!! Solve 1 1/4 + 5 5/6

2 answers:

Sedbober [7]2 years ago

6 0

Answer:

7 2/24

Step-by-step explanation:

We can start by making the denominators the same (the bottom number)

1 1/4+5 5/6

1 6/24+ 5 20/24=7 2/24

Rus_ich [418]2 years ago

3 0

Answer:

so what you would want to do is get your fraction into improper fractions and to do that you multiply the whole number by the denominator and add it to your numerator, once you do that you get 5/4, and 35/6, now we want to get common denominators, so we multiply 5/4, by 6/6, and 35/6 by 4/4 which would get us 30/24 and 140/24 then we add them and get 170/24 and then simplify, which gets you 85/12 and then put it into a mixed number which is 7 1/12

Step-by-step explanation:

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2 years ago

Which expressions are equivalent?

alexdok [17]

Answer:

I believe the one that is selected is correct.

Step-by-step explanation:

1/5k - 2/3j and -2/3j + 1/5k

If you switch the subtraction to addition, 2/3 becomes negative, while 1/5 stays the same.

4 0

2 years ago

GCF of 16 and 22 <br><br> Help

lisov135 [29]

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2 years ago

Martin is considering the expressions 12(7x+48) and − (12x−3)+4(x+5) . He wants to know if one expression is greater than the ot

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The expression 12(7x+48) is greater than (12x-3) +4(x+5)
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3 0

3 years ago

It is believed that the percentage of people who support candidate A is 56%. A sample of size 100 indicated that 40 people suppo

kondor19780726 [428]

Given data:

Sample size $=100$

Sample proportion of people support candidate A:

$p=\frac{40}{100}=0.40$

Population proportion of people support Candidate A :

$P=\frac{56}{100}=0.56$

Check the condition: $nP>10$ and $n(1-P)>10.$

$nP=100*0.40=40>10$

$n(1-P)=100*0.60=60>10$

Null Hyposthesis: $H_0: P=0.56$

Alternative Hypothesis: $H_\alpha :P\neq 0.40$

The test statistics:

$z=\frac{p-P}{\sqrt{\frac{P(1-P)}{n}}}$

Plug in p=0.56, P=0.40 and n=100 in the above formula,

$z=\frac{0.56-0.40}{\sqrt{\frac{0.40(1-0.40)}{100}}}$

$z=\frac{0.56-0.40}{\sqrt{\frac{0.40(1-0.40)}{100}}}=3.2659$

The table value of z at 10% of significance level is 1.28

Table value is less than the calculated value.

Hence $H_0$ is rejected at 10% level.

Therefore there is the evidence at an alpha level of 10% to conclude that the percentage of people who support candidate A has changed.

5 0

3 years ago