The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:
Converting moles of boric acid to mass:
Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.
A. Protons, neutrons, and electrons
Answer: the correct answer is C velocity.
Explanation: I just got the answer wrong on the exam.
Answer:
The similarity is that Elements and Compunds exist in stable form because of the bonds formed between their atoms. The difference is that an element is a material that consists of a single type of atom and a compound consists of two or more types of elements held together by covalent or ionic bonds.
Explanation: Google