Third choice because 1,5 years at 7 percent would of been kore
<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
I think you do 120 divided by 5, but I could be wrong.
Well first because in this equation the first value is less than one, we should multiply the whole equation by 3, so
<span>x/3= x+1/4
x=3x+3/4
now we should switch the values
3x+3/4=x
now subtract x from both sides
2x+3/4=0
now subtract 3/4 from both sides
2x=-3/4
now divide both sides by 2
x=3/8
So that's your answer!
</span>
Answer:
Step-by-step explanation:
Given
Required
Make t the subject
Cross Multiply
Collect Like Terms
Factorize:
Make t the subject