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2 years ago

Help me pleasse the first correct answer gets a brainliest

Mathematics

2 answers:

Yuri [45]2 years ago

7 0

Answer: 2,340

Step-by-step explanation:

First you have to find the total amount of books in the sample which is 1125 then you can see that 45 of those books have major damage. Next you need to divide 58,500 by 1125 to see how much you need to multiply 45 by which is 52. So now you need to multiply 45 by 52 which is 2340.

tigry1 [53]2 years ago

3 0

Answer:1005

Step-by-step explanation:sorry if I’m wrong I really want a like it would help a lot but I think this answer is right

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Ode to enchanted light Guiding Questions

Aleks04 [339]

You need to add what the lines are if you want them to be analysed for you^^

7 0

1 year ago

What is the 38th term of 459,450,441,..

galina1969 [7]

Answer:

The 38th term of 459,450,441,.. will be:

$a_{13}=351$

Step-by-step explanation:

Given the sequence

$459,450,441,..$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$450-459=-9,\:\quad \:441-450=-9$

$d=-9$

The first element of the sequence is

$a_1=459$

so the nth term will be

$a_n=-9\left(n-1\right)+459$

$a_n=-9n+468$

Putting n=38 to find the 38th term

$a_n=-9n+468$

$a_{13}=-9\left(13\right)+468$

$a_{13}=-117+468$

$a_{13}=351$

Therefore, the 38th term of 459,450,441,.. will be:

$a_{13}=351$

3 0

2 years ago

827 divided by 1120

KiRa [710]

It can be the last one, 827 over 1120

Hope that helps

4 0

2 years ago

Read 2 more answers

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :