All categories

2 years ago

Consider the inequality -20.2 > 0y. Which of the following must be true?

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

7 0

Answer:Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Quincy spends of his pocket money on snacks to keep in his locker. Write the fraction in decimal form.

The decimal equivalent of is .

Step-by-step explanation:Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Quincy spends of his pocket money on snacks to keep in his locker. Write the fraction in decimal form.

The decimal equivalent of is .

defon2 years ago

3 0

Answer i took the quiz

the answers r

You might be interested in

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, f = i × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, f = 1000 × $(1+\dfrac{\textrm 15}{100})^{\textrm 6}$

Or, f = 1000 × $(1.15)^{6}$

Or, f = 1000 × 2.31306

∴ f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06 Answer

3 0

2 years ago

How do you solve 8n+20=124

alexandr1967 [171]

N will be 96 because 8+20=28-124=96 hope it help

4 0

2 years ago

Read 2 more answers

Statistics students in Oxnard College sampled 10 textbooks in the Condor bookstore, and recorded number of pages in each textboo

jeka94

Answer:

y = -0.85 + 0.09x; $49.82

Step-by-step explanation:

1. Calculate Σx, Σy, Σxy, and Σx²

The calculation is tedious but not difficult.

$\begin{array}{rrrr}\mathbf{x} & \mathbf{y} & \mathbf{xy} & \mathbf{x^{2}}\\526 & 52.08 & 27394.08 & 276676\\625& 59.00 & 36875.00 &390625\\589 & 56.12 & 33054.68 & 346921\\409 & 25.72 & 10519.48 & 167281\\489 & 34.12& 16684.68 & 293121\\500 & 53.00 & 26500.00 &250000\\906 & 76.48 & 71102.88 & 820836\\251 &26.08 & 6546.08 & 63001\\595 & 50.60 & 30107.00 & 354025\\719 & 68.52 & 49265.88 & 516961\\\mathbf{5609} & \mathbf{503.72} &\mathbf{308049.76} & \mathbf{3425447}\\\end{array}$

2. Calculate the coefficients in the regression equation

$a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{503.7 \times 3425447 - 5609 \times 308049.76}{10 \times 3425447- 5609^{2}}\\\\= \dfrac{1725466163 - 1727851103.84}{34254470 - 31460881} = -\dfrac{2384941}{2793589}= \mathbf{-0.8537}$

$b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{3080498 - 2825365.48}{2793589} = \dfrac{255132}{2793589} = \mathbf{0.09133}$