a(x+1)(x-1)+b(x-2)(x+1)+(x+1)^2=9x^2-x-10
(x+1)(a(x-1)+b(x-2)+(x+1))=(x+1)(9x-10)
a(x-1)+b(x-2)+x+1=9x-10
Now this equation is much simpler!
(a+b)x-a-2b+x+1=9x-10
(a+b)x-a-2b=8x-11
(a+b-8)x-a-2b-11=0
a+b-8=(a+2b-11)/x
I can't solve it 3 variables and 1 equations means infinite answers so yea.
Answer:
It can go 250 m deep
Step-by-step explanation:
The answer you are looking for is 339
The absolute value equation with the wanted solutions is:
|x| - 1/2 = 0
<h3>
How to find the absolute value equation?</h3>
Here we want to find an absolute value equation such that the solutions are:
x = -1/2 and x = 1/2.
Remember that the absolute value equation always changes the sign, such that the outcome is positive.
This means that:
|1/2| = 1/2
|-1/2| = 1/2
Then a trivial equation with these two solutions is:
|x| - 1/2 = 0
Where the two solutions are x = 1/2 and x = -1/2.
If you want to learn more about absolute value equations:
brainly.com/question/5012769
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