The correct options are as follows:
1. In the chemical equation given above, Fe3+ IS REDUCED.
A reduction is a process in which an atom of an element gains an electron and therefore become reduced. In this type of reaction, the positive character of the atom is reduced. Looking at the equation given above, you will notice that, the positive character of Iron is reduced form +3 to +2.
2. In the reaction given above, the chlorine atom is OXIDIZED.
An oxidation is a process in which an atom loses an electron, thereby increasing its oxidation number. In this case, the positive character of the atom is increased. Looking at the chlorine atom given above, you will notice that it has a charge of -1 before and now it has change to neutral, which means that, it has given out the electron it gains earlier.
3. This type of redox reaction can not take place. This is because, in chemical reaction, the chlorine atom is always looking for another element that will donate an electron to it in order to become stable. Thus, chlorine atom easily gain electrons but it can not donate an electron to another element.<span />
Answer:
C. substances that are used up in a reaction
Explanation:
Substances are combined in a chemical reaction to give rise to other substances. The substances that come together are called REACTANTS while the substances that are produced are called PRODUCTS.
Reactants are used up in the reaction to give rise to new products at the end of the reaction. For example, in the reaction as follows:
6CO2 + 6H2O --> C6H12O6 + 6O2
CO2 (carbon dioxide) and water (H2O) are the REACTANTS of the reaction, which are used up to form glucose and oxygen (products)
The question requires that you assume complete ionization of the compound. This is:
(NH4)2 SO4 → 2 NH4 (+) + SO4 (2-)
Then, 1 mol of (NH4)2 SO4 produces 3 moles of ions: 2 moles of NH4 (+) and 1 mol of SO4 (2-)
=> 0.26 * 2 moles of NH4(+) = 0.52 moles of NH4 (+)
0.26 * 1 mol of SO4 (2-) = 0.26 moles of SO4 (2-).
Answer: 0.52 moles of ammonium ions and 0.26 moles of sulfate.ions.
Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
