2 1/4 + 1 1/2
2 + 1 = 3
1/4 + 1/2 = 1/4 + 2/4 = 3/4
so ur answer is 3 3/4 lbs of cheese in total
Answer:
50,000? This is my answer sorry if wrong
Step-by-step explanation:
Answer:
The minimum sample size needed is 125.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
For this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of , so .
What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?
This minimum sample size is n.
n is found when
So
Rounding up
The minimum sample size needed is 125.
Answer:450
Step-by-step explanation:
first subctract then add
Answer:
a 25 questions, 4 points b 19 questions
Step-by-step explanation:
a 96:100 = 24 : x
x = (100 x 24)/96 = 25 questions
100 : 25 = 4 points
b 76:100 = x : 25
x = (76 x 25)/100 = 19 questions