Answer:
the answer is your teacher just wanted to draw a triangle and get paid for it.
41 is not a composite number because you can not divide 41 with any number. Therefore, it is prime.
Answer:
m∠BCD = 140°
Step-by-step explanation:
ABCD is cyclic quadrilateral. A property of cyclic quadrilateral states that the opposite angles of it sum up to 180°. Here:
m∠A + m∠C =180° and m∠B + m∠D = 180°
So, m∠A + m∠C =180°
m∠A = 40° (given in the question)
40° + m∠C = 180°
m∠C = 180° - 40° = 140°
∴m∠C = m∠BCD = 140°
6 gives largest output and 12.7 or -.4 gives the smallest
This question is not correctly written.
Complete Question
Select all equations that can represent the question: "How many groups of 4/5 are in 1?" A ?⋅1=4/5? Times 1 is equal to 4 fifths B 1⋅4/5=?1 times 4 fifths is equal to ? C 4/5÷1=?4 fifths divided by 1 is equal to ? D ?⋅4/5=1? Times 4 fifths is equal to 1 E 1÷4/5=?1 divided by 4 fifths is equal to ?
Answer:
D ?⋅4/5=1 = ? Times 4 fifths is equal to
E 1÷4/5=? = 1 divided by 4 fifths is equal to
Step-by-step explanation:
How many groups of 4/5 are in 1?
The operation used to solve this is that Division operation.
Hence, we solve it by saying:
1 ÷ 4/5 = ?
= 1× 5/4 = ?
5/4 = ?
Cross Multiply
5 = 4 × ?
? = 5/4
The equations that can represent the question: is
Option D ?⋅4/5=1 = ? Times 4 fifths is equal to
Option E 1÷4/5=? = 1 divided by 4 fifths is equal to
