How much is 7 cups in pints Write your answer as a whole or mixed number in simplest form

You are considering adding a new food product to your store for resale. You are certain that, in a month, the minimum demand for

kolbaska11 [484]

Answer:

Using EMV analysis, the number of units of the new product should be purchased for resale = Purchase 7.

The maximum EMV of profit you can make is 270.

Explanation:

We can use the following method to solve the given problem

Solution:

Using EMV analysis,

EMV (Purchase 6 for resale)= 6(40)(0.1) + 6(40)(0.4) + 6(40)(0.5)=240

EMV (Purchase 7 for resale) = [6(40)-60](0.1) +7(40)(0.4) + 7 (40)(0.5) = 270

EMV (Purchase 8 for resale) = [6(40)-2(60)] (0.1) + [7 (40) - 60] (0.4) + 8(40)(0.5)= 260

Largest EMV= 270; Choose to purchase 7 units for resale.

Step-by-step explanation:

Hopefully this helps :)

6 0

1 year ago

Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being

Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new equipment, and this sample has a standard deviation of 0.047.

Let $\sigma$ = standard deviation of weights of new equipment.

SO, Null Hypothesis, $H_0$ : $\sigma \geq$ 0.065 {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, $H_A$ : $\sigma$ < 0.065 {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here One-sample chi-square test statistics;

T.S. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 0.047

n = sample of quarters = 25

So, the test statistics = $\frac{(25-1)\times 0.047^{2} }{0.065^{2} }$ ~ $\chi^{2}__2_4$

= 12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0

2 years ago

This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so th

Rzqust [24]

TheThe smallest diameter of wrapper that will fit the candy bar is 5cm.

<h3>Smallest diameter</h3>

Given:

AD = DC

AC = AD + DC

Segment AD = 2.5cm

Hence:

AC = AD + AD (AD = DC)

AC = 2AD

Where:

AD=2.5

So,

AC = 2(2.5cm)

AC = 5cm

Therefore the smallest diameter of wrapper that will fit the candy bar is 5cm.

Learn more about smallest diameter here: brainly.com/question/12944899

#SPJ1

3 0

1 year ago

There are 11 blue marbles and 7 red

Rufina [12.5K]

Since the blue marbles are 11 and the red marbles are 7 you start will the red marbles first because the question say red marbles to blue marbles
7:11

8 0

1 year ago

Find the force it would take to accelerate an 800-kg car at a rate of 5 m/s^2.

Mars2501 [29]

800/5 which is 160!!!!!!!!

5 0

2 years ago