Answer:
1) acetylide
2) enol
3) aldehydes
4) tautomers
5) alkynes
6) Hydroboration
7) Keto
8) methyl ketones
Explanation:
Acetylide anions (R-C≡C^-) is a strong nucleophile. Being a strong nucleophile, we can use it to open up an epoxide ring by SN2 mechanism. The attack of the acetylide ion occurs from the backside of the epoxide ring. It must attack at the less substituted side of the epoxide.
Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.
The equilibrium position may lie towards the Keto form of the compound. Usually, if terminal alkynes are used, the product of the reaction is a methyl ketone.
Answer:
Explanation:
The work function of the sodium= 495.0 kJ/mol
It means that
1 mole of electrons can be removed by applying of 495.0 kJ of energy.
Also,
1 mole =
So,
electrons can be removed by applying of 495.0 kJ of energy.
1 electron can be removed by applying of of energy.
Energy required =
Also,
1 kJ = 1000 J
So,
Energy required =
Also,
Where,
h is Plank's constant having value
c is the speed of light having value
So,
Also,
1 m = 10⁻⁹ nm
So,
Nucleotide bases bonded to a sugar phosphate backbone make up nucleic acids such as DNA (deoxyribonucleic acid) and RNA (<span>ribonucleic acid)</span>. Nucleotides have three major parts: sugars, phosphates, and a nitrogenous base. DNA uses four nitrogenous bases: Adenine, Guanine, Cytosine, and Thymine. RNA uses the same bases except for Thymine, which is replaced by Uracil.
Consider you have a mixture of amino acids(contains all set of amino acids such as polar, non polar). Other than TLC, how are you supposed to separate a single amino acid from the mixture without loss of amino acid quantitatively.