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2 years ago

12

n the diagram, ABC and DBE are similar. What is the scale factor of the dilation that will map the preimage ΔABC onto the image

ΔDBE?

1 answer:

ZanzabumX [31]2 years ago

7 0

I am not sure but I do know that you need to have coordinates points in order to be able to graph... so there for you have to make an x/y chart in order to know here to graph...

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Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

2 years ago

PLESE HELP UREGNET GEOMTERY

Dima020 [189]

D is the distance from moon to sun, and it's the hypotenuse of a right triangle.

Y is opposit to angle X

Sin (x) = y/d =

D = Y/sin(x)

3 0

2 years ago

What is 5/8 divided by 32

Citrus2011 [14]

First you need to convert 32 into a fraction, so just add 1 as the denominator; 5/8 ÷ 32/1. But you can't divide fractions, so multiply by the reciprocal. 5/8 · 1/32. You should get 5/256 as your answer. I hope that helped!

7 0

2 years ago

What is the difference of the ones and the tenth digit of the pi?

antiseptic1488 [7]

Answer:

<h3>2</h3>

Step-by-step explanation:

The value of pi is 22/7

Expressing as a decimal, the first ten digits of pi is 3.1415926535

The value in the tenth digit of the pi is 5 (tenth value after the decimal point)

The value of the ones is 3(The value before the decimal point)

The difference between both values = 5 - 3

The difference between both values = 2

Hence the difference of the ones and the tenth digit of the pi is 2

8 0

2 years ago

Simplify the equation.

maks197457 [2]

Answer:

Step-by-step explanation:

5(x-3y)+2(4x+y)-(x+y)

5x-15y+8x+2y-x-y

5x+8x-x-15y+2y-y

13x-x-13y-y

12x-12y

8 0

2 years ago

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