2 years ago

Write three primary alcohol with the formula C4H8O

Chemistry

1 answer:

pishuonlain [190]2 years ago

3 0

Answer:

CH2 will be CH-CH2-CH2OH

CH3-CH will beCH-CH2OH

CH2 will be C(CH3)-CH2OH

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A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of

mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

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To reach 12.5% of reactant means that 0.125 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.125

t = ?

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

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t = 473 year

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2 years ago

Write three primary alcohol with the formula C4H8O​

Write three primary alcohol with the formula C4H8O