Answer: can you explain it more?
Step-by-step explanation:
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.
So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))
now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16
Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84
So we have our linear approximation for the two.
If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35
So just to check our linear approximations use that to find g(2.99) and g(3.01)
g(2.99) = -5.1597
g(3.01) = -4.8397
So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.
So the equation you're going to be using is mass = density x volume
So the volume of your block is 35cm^3, and your density is .85g/ml
so your equation would be
mass=.85g/ml x 35cm^3
your final answer is 29.75g/cm^3
Hope this helps :)
Answer:
Range= $144,000
Step-by-step explanation:
The least amount for each car is 22,000 and the highest is 25,000
so assuming the dealer sells all of them the lowest price, the revenue would be, $1,056,000 (that would be the lowest revenue) and assuming he sells all the cars at the highest price, the dealer will get a revenue of $1,200,000. So the lowest revenue is 1,056,000 and the highest revenue is 1,200,000. So to find the range subtract the highest revenue by the lowest and you’ll get $144,000.