Answer:
26.8907563 or if your rounding it then 26.7
Step-by-step explanation:
Answer:
biotbhuvb2tupbpu2
Step-by-step explanation:
Answer:
-9 = 0.45m
Step-by-step explanation:
- ^ Subtract 0.45m from BOTH sides. so
... etc - Why? So that we can make the equation less complicated. Our goal is to isolate the variable m to be on one side of the "=" sign by itself
- That will equal to:
<-- ANSWER
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
Answer:
x = 2 + 6i, x - 6i.
Step-by-step explanation:
To factor this you need 2 numbers whose product is + 40 and whose sum is -4. There are no such numbers so we could use the method of completing the square:
x^2 - 4x + 40 = 90
x^2 - 4x = -40
(x - 2)^2 - 4 = -40
(x - 2)^2 = -36 - So the roots are complex numbers:
x - 2 = +/-√36
x = 2 + 6i, x - 6i.
