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1 year ago

expand and simplify completely (log). PLEASEE HELP ASAP!!! I WILL GIVE BRAINLIEST!! thank you so much!!!!

Mathematics

2 answers:

r-ruslan [8.4K]1 year ago

7 0

Answer:

c. $2 log3(y)+1+log3(x)$

Step-by-step explanation:

When expanding and simplifying, we can see that the answer is $1+log3(x) + 2log3(y)$ , which matches Answer Choice C.

lisov135 [29]1 year ago

3 0

Answer:

( C ) 1+log3x+2log3y

Step-by-step explanation:

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X=y+2

Andreas93 [3]

Answer:

4=8 908575939835

Step-by-step explanation:

lol

8 0

2 years ago

Tabular representations for the functions f, g, and h are given below. Write g(x) and h(x) as transformations of f(x).

Leto [7]

Answer:

the answer for g is -3 that is all I know

4 0

1 year ago

Read 2 more answers

You want to make an angle measuring 35° by marking an arc on the perimeter of a disk with a diameter of 16 inches and drawing li

Margaret [11]

The arc length is given by
.. s = rθ . . . . . . θ is the central angle in radians
.. = (8 in)*(35/180*π)
.. ≈ 4.9 in

_____
A disk 16 inches in diameter has a radius of 8 inches.

6 0

2 years ago

If f(x)=x+11 and g(x)=3x^2, find (f+g)(x) and (f+g)(5).

Stella [2.4K]

(f+g)(x) = f(x) + g(x) = x + 11 + 3x^2
(f+g)(5) = f(5) + g(5) = 5 + 11 +3(5^2) = 91

8 0

2 years ago

I NEED HELP PLEASEE

xenn [34]

$\bf \cfrac{1+cot^2(\theta )}{1+csc(\theta )}=\cfrac{1}{sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\implies \cfrac{1+\frac{cos^2(\theta )}{sin^2(\theta )}}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{sin^2(\theta )+cos^2(\theta )}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin^2(\theta )}~~}{\frac{sin(\theta )+1}{sin(\theta )}}$

$\bf \cfrac{1}{\underset{sin(\theta )}{~~\begin{matrix} sin^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}\cdot \cfrac{~~\begin{matrix} sin(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{sin(\theta )+1}\implies \cfrac{1}{sin^2(\theta )+sin(\theta )} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{1+cot^2(\theta )}{1+csc(\theta )}\ne \cfrac{1}{sin(\theta )}~\hfill$

5 0

2 years ago