A mixture can always be called a solution when its homogeneous.
The energy density is calculated by dividing the energy given by the mass of the material. From this item, the energy is 78 kcal and the mass is 50 grams. Performing the operation will give us an answer of 1.56 kcal/grams.
Answer:
The composition of Mg(OH)2 is
41.67 % Mg,
54.87 % O
3.457 % H
Explanation:
Thats the percent composition for each one in your question
Answer:
The concentration of fructose-6-phosphate F6P ≅ 1.35 mM
Explanation:
Given that:
ΔG°′ is the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) = +1.67 kJ/mol = 1670 J/mol
concentration of glucose-6-phosphate at equilibrium = 2.65 mM
Assuming temperature = 25.0°C
=( 25 + 273)K
= 298 K
We are to find the concentration of fructose-6-phosphate
Using the relation;
ΔG' = -RT In K_c
where;
R = 8.314 J/K/mol
1670 = - (8.314 × 298 ) In K_c
1670 = -2477.572 × In K_c
1670/ 2477.572 = In K_c
0.67 = In K_c
0.511
Now using the equilibrium constant
F6P = 0.511 × 2.65
F6P = 1.35415
F6P ≅ 1.35 mM