Ask question

Ask question

All categories

1 year ago

12

If a dog that has moved has a displacement of zero, it means that the dog's initial position and final position are the same. Is

it T or F

1 answer:

Aliun [14]1 year ago

6 0

Answer:

true

Explanation:

the dog hasn't moved, displacement has direction, and there is no movement or direction involved, his final position and initial are the same

You might be interested in

A woman using a compass and a map walks 132 east of north for 6 km

ANEK [815]

If she walks 132 and 6 you do 132 x 6 = 792

7 0

2 years ago

Read 2 more answers

A man of 60kg moves in a lift of constant velocity 5m/s .What is the reactive force acting on the man by the elevator?

Flauer [41]

Answer:

588 N

Explanation:

Since the 60 kg is moving at a constant velocity there is no acceleration. In order for the system to be balanced, both the normal force and the force of gravity must be equal. In this case the man has a mass of 60 kg. So to find the force you multiply mass by gravitys constant (9.81). And you end up with an answer of 588.6 but I rounded to 588.

4 0

2 years ago

Read 2 more answers

A long solenoid with 8.22 turns/cm and a radius of 7.00 cm carries a current of 19.4 mA. A current of 3.59 A exists in a straigh

daser333 [38]

Answer:

a. 3.039cm

b.magnetic field is $B=2.958\times10^{-5}T$

Explanation:

Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:

$\overrightarrow B = \overrightarrow B_s+ \overrightarrow B_w,\ \ \ \ \ \overrightarrow B_s\perp \overrightarrow B_w$

Angle of net magnetic field from axial direction is given by:

$tan\ \theta=\frac{B_w}{B_s}$ ,

Field due to solenoid:

$B_s=\mu_onI_s, \ \ \ \ n=(8.22 t/cm)(100cm/m)=822turn/m$

Field due to wire:

$B_w=\frac{\mu_oI_w}{2\pi r}$

Therefore, r:

$tan\ \theta=\frac{B_w}{B_s}\\\\=\frac{\mu_oI_w}{2\pi r(\mu_o nI_s)}\\\\r=\frac{I_w}{2\pi nI_stan \ \theta}\\\\r=\frac{3.59A}{2\pi\times822\times19.4\times10^{-3}A \ tan 49.7\textdegree}\\\\r=3.039cm$

Hence, the radial distance is 3.039cm

b.The magnetic field strength is given by:

$B=\sqrt{B_w^2+B_s^2}\\\\tan 49.7\textdegree=\frac{B_w}{B_s}\\\\1.179=\frac{B_w}{B_s}\\\\B_w=1.179B_s\\\\B=\sqrt{(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{3}A)+1.179(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{-3}A)}\\\\B=2.958\times10^{-5}T$

Hence, the magnetic field is $B=2.958\times10^{-5}T$

7 0

2 years ago

Ann puts a beaker on the scale which shows the mass to be 1.65kg. The actual mass was 1.72 kg. what was the percent error in Ann

mojhsa [17]

Measured reading is 1.65 kg

actual reading was 1.72 kg

error in the reading is 1.72 - 1.65 = 0.07 kg

Now percentage error is given as

$error = \frac{error}{true reading}*100$

$error = \frac{0.07}{1.72}*100$

$error = 4.1$

<em>so this is -4.1% error as the measured reading is less than the actual value</em>

8 0

2 years ago

How much of a kilogram is a gram?

Bond [772]

1000 grams = 1 kilogram

3 0

2 years ago