2 years ago

The grass on Julie's lawn was 4.5 centimeters tall right after she mowed it. Then the grass

Mathematics

1 answer:

telo118 [61]2 years ago

4 0

Answer: w = 2.1h + 4.5

Step-by-step explanation:

w is the number of weeks since Julie mowed the lawn

h is the height of the grass

w=the rate the grass grew at and the grass on Julies lawn

w=2.1h+4.5

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Mrs. Trotta drives a total of 378 miles over 6 days. She drives the same amount of miles each day. How many miles does Mrs. Trot

Vesna [10]

378/6=63 miles per day

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2 years ago

A rock is thrown from the top of a tall building.The distance in feet between the rock and the ground t seconds after thrown is

marusya05 [52]

Answer:

0.448 seconds

Step-by-step explanation:

d = -16t² -4t + 412

find t when d = 407

substituting d = 407 into the equation:

407 = -16t² -4t + 412 (subtract 407 from both sides)

-16t² -4t + 412 - 407 = 0

-16t² -4t + 5 = 0 (multiply both sides by -1)

16t² + 4t - 5 = 0

solving using your method of choice (i.e completing the square or using the quadratic equation), you will end up with

t = (-1/8) (1 + √21)= -0.70 seconds (not possible because time cannot be negative)

t = (-1/8) (1 -√21) = 0.448 seconds (answer)

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2 years ago

How many, and what type of, solutions does 4x² + 12x + 9 = 0 have?

Gemiola [76]

1 rational solution

4x² + 12x + 9 = 0
(2x+3)²=0
2x + 3 =0
2x +3 -3 = 0-3
2x = -3
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2 years ago

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Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th

timurjin [86]

Answer:

35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

$E(X) = \frac{10,000 +1,000}{2} \\E(X) =\$5,500$

If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

$E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56$

The percentage reduction on the claim payment is:

$P=(1-\frac{E_2(X)}{E(X)})*100 \\P=(1-\frac{3,555.56}{5,500})*100\\P=35.35\%$

There was a 35.35% reduction.

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2 years ago

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marishachu [46]

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