1. find slope
x=tickets sold
y=money made
slope=(y2-y1)/(x2-x1)
take any point
(5,23.75) and (10,47.50)
input (note, (x,y))
(47.50-23.75)/(10-5)=23.75/5=4.75
slope=4.75
y=mx+b
m=slope
b=yintercept
y=4.75x+b
input
47.5=4.75(10)+b
47.5=47.5+b
b=0
equation is y=4.75x
if ticket sold is 24 then x=24
y=4.75(24)
y=114
answer is $114
2. points
(0,56.00) and (3,45.5)
slope=(y2-y1)/(x2-x1)
slope=(45.5-56.00)/(3-0)=-3.5
y=-3.5x
slope=-3.5
logic it yourself
equation is
y=-3.5x+0
y intercept is when x=0 so when the start of it was or when time=0
x intercept is when y=0 is when he has no money left
1.a. rate of change=4.75
b. $114
2. a.do this yourself, (desmos graphing calculator)
b. slope=-3.5 (duh, means money goes down with time)
c. equaiton is y=-3.5x+0, xint meanss when he has no money, y int means when time=0 or when it started
Answer:
A) The functions are not inverses of each other.
Step-by-step explanation:
The result of f(g(x)) is not always x, so the functions are not inverses of each other.
In general, a quadratic (or any even-degree polynomial) such as g(x) cannot have an inverse function because it does not pass the horizontal line test.
1st slope is -1/3. 2nd slope is 6
slope is same in parallel lines so not parallel
slopes are negative reciprocals in perpendicular lines so they aren't perpendicular
they are called oblique
Answer:
AC=BD
CAD=CBD
ACB=ADB
Step-by-step explanation:
You're essentially looking for anything of equal proportions. Obviously, your circle is split by several lines, and each side is symmetric. Since you know this, it's simply a matter of identifying one element then finding its symmetric match.
Follow the lines and trace the path with your finger for each question. If you do this, you'll see that AC=BD is an answer that involves a symmetric pair, because these two are equal distances and equal (but opposite) in placement.
Continuing with this method, keep track of the parts of the triangles you trace. With CAD=CBD, you trace across a hypotenuse, a leg, and a base in BOTH, making this true.
Continuing further with ACB=ADB, you trace across a hypotenuse, a leg, and a base with both AGAIN, making this true.
With AB=CD, this is obviously incorrect. You can't jump between points.
AP teachers for<span> course and exam preparation; permission </span>for<span> any other use ... 3. Question 2. Let f and g be the functions given by ( ). (. ) 2 1. </span>f x<span> x x. = − and. ( ) (. ) ..... </span>Let f be the function given by<span> ( ). ( ) </span>sin<span> 5. ,. </span>4<span>. </span>f x<span> x </span>π<span>. = + and let ( ). P x be the ...</span>
