How do you prepare copper sulphate

1 answer:

Elena-2011 [213]2 years ago

4 0

Prepare a 1% copper sulfate solution. To make this solution, weigh 1 gram of copper sulfate (CuSO4 ·5H2O), dissolve in a small amount of distilled water in a 100 ml volumetric flask and bring to volume. Label this as 1% copper sulfate solution.

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Calcium cyanamide, CaCN2, reacts with water to form calcium carbonate and ammonia. CaCN2(s)+3H2O(l)→CaCO3(s)+2NH3(g). How many g

Norma-Jean [14]

298 g of calcium carbonate CaCO₃

Explanation:

We have the following chemical reaction:

CaCN₂ (s) + 3 H₂O (l) → CaCO₃ (s)+ 2 NH₃ (g)

number of moles = mass / molar weight

number of moles of H₂O = 161 / 18 = 8.94 moles

Knowing the chemical reaction we devise the following reasoning:

if 3 moles of H₂O produces 1 mole of CaCO₃

then 8.94 moles of H₂O produces X moles of CaCO₃

X = (8.94 × 1) / 3 = 2.98 moles of CaCO₃

mass = number of moles × molar weight

mass of CaCO₃ = 2.98 × 100 = 298 g

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number of moles

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7 0

2 years ago

if the percent by volume is 2% and the volume of solution is 250 mL what is the volume of solute and solution

Liula [17]

Answer:

Solute = 5 mL; solution = 250 mL

Explanation:

The formula for percent by volume is

$\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%$

If you have 250 mL of a solution that is 2 % v/v,

$\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}$