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2 years ago

Help me plz nowwwwww

Mathematics

1 answer:

Ymorist [56]2 years ago

5 0

Answer:

...

Step-by-step explanation:

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What is the tangent ratio for ∠A?<br><br><br>6/8<br><br><br>8/6<br><br><br>10/8<br><br><br>8/10

makkiz [27]

Tangent is Opposite over adjacent.

The opposite side of Angle A is 6 and the adjacent side is 8.

The tangent ratio would be 6/8

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2 years ago

Graph the system of linear inequalities.<br> y > 3x + 2<br> y ≤ 3x − 4

Alisiya [41]

$y > 3 \times 2 \\ solve \: for \: y \\ y > 6 \\ ye \: {6 + \infty }$

Sorry that's all i know

<h3>that is in my answer</h3>

<h2>#carryonlearning:-D</h2>

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2 years ago

PLZZZ NEED HELP!!!!!!

Nuetrik [128]

Uhh thats a test...... a or b

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2 years ago

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If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

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2 years ago

Read 2 more answers

If vector u = <-3.5, -1.5> and vector v = <-1.25, 2.25>, which graph shows the resulting vector for 2v − u?

Sedaia [141]

Answer:

Step-by-step explanation:

We know that vector addition is scalar addition.

Given vectors are u = <-3.5, -1.5> and v = <-1.25, 2.25>

2v = < -2.5, 4.5>

2v - u = < -2.5, 4.5> - <-3.5, -1.5> = < -2.5 - (-3.5) , 4.5 -(-1.5) >

2v-u = < 1 , 6 >

This vector is basically i + 6j which is drawn in option D

8 0

2 years ago