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2 years ago

15

HARD QUADRATICS!!!! A quadratic of the form $-2x^2 + bx + c$ has roots of $x = 3 + \sqrt{5}$ and $x = 3 - \sqrt{5}.$ The graph o

f $y = -2x^2 + bx + c$ is a parabola. Find the vertex of this parabola.

1 answer:

iren2701 [21]2 years ago

5 0

Answer:

hold up this will take a min to work out

Step-by-step explanation:

You might be interested in

How do you fraction decimals and percents and all of that

Korvikt [17]

From fraction to decimal: divide the numerator by the denominator

From decimal to percent: move the decimal two places to the right. For example: 0.062=6.2%

From percent to decimal: move the decimal point two steps to the left. For example: 56%=0.56

From decimal to fraction: Rewrite the decimal number number as a fraction (example: <span>2.625=<span>2.6251</span></span>) an then Multiply by 1 to eliminate 3 decimal places, we multiply numerator and denominator by 10 cubed = 1000<span><span><span>2.625/1</span>×<span>1000/1000</span>=<span>2625/1000 and don forget to reduce if possible;)

</span></span></span>

3 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

1 year ago

Solve for x.<br><br> -5(x – 4) = -30<br><br> Enter your answer in the box.<br><br> x =

Svetlanka [38]

Answer:

$- 5(x - 4) = 30$

$- 5x + 20 = 30$

$- 5x = 30 - 20 = 10$

$x = 10 \div - 5$

$x = - 2$

3 0

2 years ago

Read 2 more answers

Please answer quickly!

Serhud [2]

Answer:

tanx

Step-by-step explanation:

tan=TOA

opp/adj

x=p/r

4 0

2 years ago

Scores on the Wechsler intelligence quotient (IQ) test for adults have a normal probability distribution with a mean score of 10

bixtya [17]

Answer:

Probability = 0.1587

Step-by-step explanation:

The provided information is:

Let X be the scores of the IQ test for adults that is normally distributed with mean $(\mu)$ = 100 and standard deviation $(\sigma)$ = 15.

Also, US military has minimum IQ score of 85.

Thus, the probability that randomly selected adult does not meet US military enlistment standards is: $P(X$

The probability can also be written as:

$P(X < x) =P(Z$

Thus,

$P(X$

Using the Normal probability table probability of Z = -1 is 0.1587

Thus, the required probability is 0.1587

8 0

2 years ago