Answer:
A) x ≤ -2 and 0 ≤ x ≤ 3
Step-by-step explanation:
g(x) is decreasing when g'(x) is negative.
Use second fundamental theorem of calculus to find g'(x).
g(x) = ∫₋₁ˣ (t³ − t² − 6t) / √(t² + 7) dt
g'(x) = (x³ − x² − 6x) / √(x² + 7) (1)
To find when g'(x) is negative, first find where it is 0.
0 = (x³ − x² − 6x) / √(x² + 7)
0 = x³ − x² − 6x
0 = x (x² − x − 6)
0 = x (x − 3) (x + 2)
x = -2, 0, or 3
Check the intervals before and after each zero.
x < -2, g'(x) < 0
-2 < x < 0, g'(x) > 0
0 < x < 3, g'(x) < 0
3 < x, g'(x) > 0
g(x) is decreasing on the intervals x ≤ -2 and 0 ≤ x ≤ 3.
A line may be described as a set of points going straight on forever in two opposite directions, and they are straight and never end. A line segment is the set of any two points on a line that are the endpoints. Then a ray is a set of collinear points going in 1 direction with one endpoint. So a line is <-----> and segment is .----. (the periods are endpoints) and .----> To be frank, the differnce between a line segment and a ray is a line segment has two endpoints and stays within those endpoints and a ray has one endpoint and continues continuously in the direction opposite of the endpoint. Then the difference between a line and line segment is that a line is never-ending and and goes in two directions in a straight line, and a line segment has two endpoints and stays within them
Answer:
I need to know the cost of one visit
You would need about 8 cups more. If you make 2 2/3 a improper fraction and then multiply it by three, you would get 24/3, which is eight in simplest form.
Answer: 3 + x = 5.
Step-by-step explanation:
2 + 3 = 5, if 2 = x. Hope this helps :)
