Answer:
Multiply by 4
Step-by-step explanation:
The next number would be -320
◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
The standard form of a quadratic equation is
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by
, without the 9. So we can write:
, and substituting in
we have:
.
Finally, distributing 3 over the two terms in the brackets we have:
.
Answer:
Answer:
C) f(x) = 6.25x + 3
Step-by-step explanation:
In order to know which one of the functions could produce the results in the table we simply need to substitute the number of candy bars for x in the function and solve it to see if it provides the correct total weight shown in the table. If we do this with the functions provided we can see that the only one that provides accurate results would be
f(x) = 6.25x + 3
We can input the # of candies for x and see that it provides the exact results every time as seen in the table.
f(x) = 6.25(1) + 3 = 9.25
f(x) = 6.25(2) + 3 = 15.50
f(x) = 6.25(3) + 3 = 21.75
f(x) = 6.25(4) + 3 = 28
Answer: rounded: 2400
60 * 40
Actual: 2508
Step-by-step explanation: